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Deriving a type in PL/SQL (Inheritance) | ||
Assuming there is already a type named ABC having a member function foo, the following construct creates a new type (not body) that inherits from ABC:
create or replace type XYZ under ABC ( member_var varchar2(30), constructor function XYZ return self as result, constructor function XYZ(num in number) return self as result, overriding member function foo(bar in number) return baz );
By the way, in order to be able to derive from a base type, the base type must be declared
not final.
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